Displaying Database's Row Value In Javascript Function In Php

$finalval=0; while($row = mysql_fetch_array($result)) { $finalval=$finalval. ''. $row['Title'] . '

Solution 1:

When you call showContent(), you have to put the ID you want to show between ", like this:

$finalval=$finalval. "<a href='#' onClick='showContent(\"".json_encode($row['ID'])."\");'>".  $row['Title'] . "</a> <br>"

Solution 2:

Try this one

<?PHP$result = mysql_query($query);
    $finalval = 0;
    while ($row = mysql_fetch_array($result)) {
         $finalval = $finalval."<a class='show-content' data-id='". $row['ID'] ."' href='#' >".  $row['Title']   ."</a> <br>" ;
    }
    echo$finalval;
?><scriptlanguage="javascript"type="text/javascript"  >var element = document.querySelectorAll(".show-content");
    for (var link in element) {
       element[link].onclick = function() {
             showContent(this.getAttribute('data-id'));
       };
    }
   functionshowContent(value){
       alert(value);
   }
 </script>